99.83.1 Rubidium and Quark Energies (Iuliano)
Page 83
Sections List- 99 Electrons and Mythologies
Impossible Correspondence Index
From: Jerryiuliano@aol.com
To: rgrace@rgrace.org
Subject: Rubidium and Quark Energies
Date: 03/05/03
Sir:
There is a strange mathematical relationship that exists between the six quark mass/energy values and the Rubidium atom...Rub. By segregating the quark spin values, 2/3 and -1/3, into the numerator and denominator of a ratio and by factoring each quark into a product of quarks proton masses and the fourth root of quarks in Giga-electron volts..Gev.. the atomic weight ( 85.4678 mol ) and atomic number ( 37 ) of the Rubidium atom are
created:
QUARKS IN PROTON MASSES...pm
Source...Brian Greene's book, " THE ELEGANT UNIVERSE " , page 9
T = top
quark = 189 pm...exact...2/3
spin
C = charm
quark = 1.6 pm...exact...2/3 spin
U = up
quark = .0047 pm...exact...2/3
spin
B =
bottom quark = 5.2 pm ...exact...1/3 spin
S =
strange quark = .16 pm...exact...1/3 spin
D = down
quark = .0074 pm...exact...1/3 spin ...as noted in
formulas
QUARKS IN GIGA - ELECTRON
VOLTS...Gev
Source...May, 2003 , Special Addition, Scientific American , page 63
t = top quark
= 174 Gev...exact
c = charm quark
= 1.3 Gev....exact
u = up quark
= .03 Gev...exact
b = bottom quark
= 4.3 Gev...exact
s = strange quark
= .14 Gev...exact
d = down quark
= .06 Gev...exact
RUBIDIUM ATOMIC WEIGHT = Rbaw =
85.4678 mol....exact
RUBIDIUM ATOMIC NUMBER = Rban =
37....exact
GIOGGI CONSTANT = 10 ^ 7 = 4* Pi * E
* ( c ^ 2 ) ...exact
E = permittivity
of space, electric constant = 8.854187818 * ( 10 ^ -12 )...exact
c = speed of light
metric = 299792458 m/s...exact
RUBIDIUM ATOMIC NUMBER...37 =
Rban
( T * C * U /
B / S / D ) * (( t * c * u / b / s / d ) ^ ( 1/4 )) = sqrt Gioggi / Rban *
10
....where D = .007399878192..
RUBIDIUM ATOMIC WEIGHT...85.4678 mol
= Rbaw
( T * C * U / B /
S / D ) * (( t * c * u / b / s / d ) ^ ( 1/4 )) = Rbaw * 10
....where
D = .007399805792..
...reducing the Gioggi constant leads
to:
( T * C * U / B / S / D ) * (( t * c * u / b / s / d ) ^
( 1/4 )) = c * sqrt( Pi * E ) * 20 / Rban
...where D = .007399878192..
The fine structure constant...aem =
1/137.036000986, the amplitude for a photon to be stripped from a proton via the
electron, separates the dual reference systems , proton masses and
giga-electron volts:
PROTON
MASSES.....037pn = hydrogen radius = Rban / 1000
T * S * U * .037 / B / C / D = sqrt aem
...where D = .00739904005..
ELECTRON
VOLTS...Gev:
( b * s * d / 100 / t / c / u ) ^ ( 1/4 ) = sqrt aem
...where d = .060027189..
The philosophy of DG Leahy's "
thinking NOW, created 100 " is the prime mover behind this system because it
seems to transform the electron volt energies (thinking NOW) of the quark
forms into real(created) proton masses via an integer (100) mass to
energy exchanging equation that is parametrized by the dimensionless
number ...fine-structure constant.
J.Iuliano
___________________________________
99.83.2 Phi derivative of the meter and Egyptian cubit (Iuliano)
From: Jerryiuliano@aol.com
To: rgrace@rgrace.org
Subject: Phi derivative of the meter and Egyptian cubit
Date: 03/05/03
Sir:
The following equations proves the hypothesis that the Egyptian Cubit was the precursor of the modern metric system, clarified mathematically as functions of Natures static metric ..phi... and Natures electrical metric.... the dimensionless fine-structure constant:
Flinders Petrie ...1888 expedition to Egypt ... Egyptian cubit = 20.632 inches
Note:
From: "Larry Brasseur"
To: "Robert Grace"
Date: Fri, July 23, 2004 7:39 pm
On your site update 07/03/04 e-mail conversations: electrons:
Title : Derivative of the meter and the Egyptian Cubic
The Egyptian = 20.632 this is taken from the Imperial measure 1 x 2.54 = 2.54 cm. and is used in most calculations. My Canadian Inch , measure is the egyptian cubic = 21 Canadian inches. If you look on my web page Canadian inch and Egyptian measure 2500 BC. you will see that i have demonstrated that the cubic is binary and if we square 21 it equals 441 remove 1 for zero = 440 for the tone of A indicating the cubic was built to harmonic specifications. Ask your friend to use my 21 instead of 20.632 and i think he will find things will work out better for his calculations. Larry. ----- End Note -----
EC:inches = Egyptian cubit...as noted
phi = 1.6180339875...exact
288 = Hebrew/Leahy" 288 sparks from broken vessels"...exact
meter:inches = 39.370074..inches...exact
c:meter = speed of light =- 299792458 meters-length/seconds-time...exact
.37 = Beta, anomalous exponent for all second-order phase transitions, liquids , metals and gases
GOLDEN SECTION FORMULA...1.6180339875.. = phi..EC = 20.632047706 inches
50000 / (( meter:inches / EC:inches ) ^ 16) = phi
BETA FORMULA.....37 = Beta
c:meter / (( phi / 50000 ) ^ ( 1/16 )) / meter:inches / ( 288 ^ 3 ) = .370000075..
FINE-STRUCTURE CONSTANT.....aem = 1/137.036000986..dimensionless
((( c:meter / EC:inches / ( 288 ^ 3 )) ^ 2 ) / ( 10 ^ ( 2 / Pi ) ) = sqrt aem
EC = 20.6320329438 inches
Since the Cheops Pyramid constructs are of the 2/Pi ratio, the link is obvious.
J.Iuliano
___________________________________
99.83.3 Megalithic Yard and Ancient/Modern Metrology (Iuliano)
Subject: Megalithic Yard and Ancient/Modern Metrology
From: JerryIuliano@aol.com
Date: Tue, March 16, 2004 6:40 pm
To: rgrace@rgrace.org
MP:
Contemplate this formula:
Letting:
Feigenbaum delta constant = 4.669201609...exact
F = 4.6692034868...used in formula
c = speed of light in meters per second = 299792458 m/s...exact
Pi = 3.141592654...exact tangent in radians
...then this equivalency can be shown:
F * Pi * ( 10^4 ) / 18 = c / (( tan F ) ^ ( -1/Pi )) / ( 10^5 )
8149.297429... = 8149.297423...
The derivation of this formula has ancient origins. After many years
of studious research of ancient megalithic stone structures , Alexander Thom determined the megalithic yard to be exactly 2.72 feet + or - .0003 feet. The metrology of the megalithic yard expressed in English units is the link to the two formulas.
...using exact value for feigenbaum constant...F = 4.669201609... one has:
F = 18 * ( 2.719999901 ^ 9 ) / Pi / ( 10^4 )
....and:
c = (( tan F ) ^ ( -1/Pi )) * ( 2.719995834 ^ 9 ) * ( 10^5 )
One can also substitute the cosine of inverse fine-structure constant...aem... for ( tan F ) ^ ( -1/Pi): aem = 1/137.036000986...cosine in radians:
cos 1/aem = cos 137.036000986... = .367872975
...so that cosine in radians:
c = ( cos 137.036000986 ) * ( 2.720001866 ^ 9 ) * (10^5 )
....or using the 82944 harmonic:
c = ( 82944 ^ ( 1/Pi )) * ( 2.720001866 ^ 9 ) * (10^3 )
...the radian ...180 / Pi.... is hidden in the formula because of 18:
radian * ( 2.719999901 ^ 9 ) / ( 10^5 ) = Feigenbaum constant..exact
J.Iuliano
___________________________________
99.83.4 Angular Measuring System: Degrees / Radian Link (Iuliano)
From: Jerryiuliano@aol.com
To: rgrace@rgrace.org
Subject: Angular Measuring System: Degrees / Radian Link
Date: 03/23/04
MP:
From the unification equation, uniting
two angular measuring systems..DEGREES...Sumerian ( 360 )..and RADIAN...1/2 Sumerian divided by Pi..180 / Pi = 57.29577951.. cosine = cos ...radians and COSINE = COS...degrees:
Letting fine-structure constant = 1/137.036004346 = aem
...then it can be demonstrated: i =
sqrt( - 1 )
(( cos 137.036004346 ) ^ (
COS 137.036004346 )) / 10 = i ^ i = 1 / sqrt ( e^Pi )
...solving for exponential x using
master harmonic 82944 in this form:
82944 ^ x = COS 137.036004346...degrees
...leads to the following
reduction:
82944 ^ -.027571485 = COS 137.036004346...degrees
...which decays (natural log e ) to
the electron in million electron volts:
(( e ^ ( e ^ (
e ^ -.027571485 ))) / 10 ) / cos 137.036004346 = 1/ ( emev ^ 2 )
...where emev = .5109981152 mev....(
2002 NIST = .510998918 mev )
The master harmonic 82944 is
equivalent through the electron form:
((( e ^ ( e ^ ( e ^ -.027571485 ))) *
37 * 17.9995953 ) ^ ( emev ^ ( - 1/Pi )) = 82944
...where emev = exact 2002 NIST
value = .510998918... mev
J.Iuliano